What is the answer to log_{2}(4x)+log_{2}(x-2)=5 ?

The answer to log_{2}(4x)+log_{2}(x-2)=5 is x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(4x)+log_{2}(x-2)=5

lo g_{2} (4 x) + lo g_{2} (x - 2) = 5

x = 4

Solution steps

lo g_{2} (4 x) + lo g_{2} (x - 2) = 5

Apply log rules

4 x (x - 2) = 32

Solve

4 x (x - 2) = 32 : x = 4, x = - 2

x = 4, x = - 2

Verify Solutions:

x = 4

True

, x = - 2

False

The solution is

x = 4

x, 4 = 2 lo g_{9} (6 x + 6)

\frac{ln ( 2 )}{ln ( a )} = 11

17 - ln (3 - x) = 0

ln (2^{4} - x) = 0

lo g_{10} (1 + x) (0.1) = 72

What is the answer to log_{2}(4x)+log_{2}(x-2)=5 ?
The answer to log_{2}(4x)+log_{2}(x-2)=5 is x=4
Solve for x: log_{2}(4x)+log_{2}(x-2)=5
The solution is x=4