What is the answer to ln(1+6y-2y^2)=0 ?

The answer to ln(1+6y-2y^2)=0 is y=0,y=3

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ln(1+6y-2y^2)=0

ln (1 + 6 y - 2 y^{2}) = 0

y = 0, y = 3

Solution steps

ln (1 + 6 y - 2 y^{2}) = 0

Apply log rules

1 + 6 y - 2 y^{2} = 1

Solve

1 + 6 y - 2 y^{2} = 1 : y = 0, y = 3

y = 0, y = 3

ln (11.7 - 2.5 x) = x - 4

lo g_{4} (x + 7) = 3

2 lo g_{2} (4 x + 1) - 1 = 6

lo g_{6} (x + 27) - lo g_{6} (x - 8) = 2

lo g_{4} (x - 4) = 1 - lo g_{4} (x)

What is the answer to ln(1+6y-2y^2)=0 ?
The answer to ln(1+6y-2y^2)=0 is y=0,y=3
Solve for y: ln(1+6y-2y^2)=0
The solution is y=0,y=3