What is the answer to log_{6}(x+27)-log_{6}(x-8)=2 ?

The answer to log_{6}(x+27)-log_{6}(x-8)=2 is x=9

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log_{6}(x+27)-log_{6}(x-8)=2

lo g_{6} (x + 27) - lo g_{6} (x - 8) = 2

x = 9

Solution steps

lo g_{6} (x + 27) - lo g_{6} (x - 8) = 2

Add

lo g_{6} (x - 8)

to both sides

lo g_{6} (x + 27) - lo g_{6} (x - 8) + lo g_{6} (x - 8) = 2 + lo g_{6} (x - 8)

Simplify

lo g_{6} (x + 27) = 2 + lo g_{6} (x - 8)

Apply log rules

x + 27 = 36 (x - 8)

Solve

x + 27 = 36 (x - 8) : x = 9

x = 9

Verify Solutions:

x = 9

True

The solution is

x = 9

lo g_{4} (x - 4) = 1 - lo g_{4} (x)

lo g_{3} (9 x) = 5 - lo g_{3} (8)

y, lo g_{e} (y) = x

lo g_{2} (- 4 x^{2} + 12 x) = 3

0.21 = 0.0592 ln (x)

What is the answer to log_{6}(x+27)-log_{6}(x-8)=2 ?
The answer to log_{6}(x+27)-log_{6}(x-8)=2 is x=9
Solve for x: log_{6}(x+27)-log_{6}(x-8)=2
The solution is x=9