What is the answer to 1/y =ln(y) ?

The answer to 1/y =ln(y) is y= 1/(\W_{0)(1)}

Solve for y: 1/y =ln(y)

The solution is y= 1/(\W_{0)(1)}

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\frac{1}{y} = ln (y)

y = \frac{1}{W _{0} ( 1 )}

Solution steps

\frac{1}{y} = ln (y)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{\frac{1}{y}} = e^{l n (y)}

Simplify

e^{l n (y)} : y

e^{\frac{1}{y}} = y

Solve

e^{\frac{1}{y}} = y : y = \frac{1}{W _{0} ( 1 )}

y = \frac{1}{W _{0} ( 1 )}

Verify Solutions:

y = \frac{1}{W _{0} ( 1 )}

True

The solution is

y = \frac{1}{W _{0} ( 1 )}

lo g_{2} (\frac{3}{4} x + 4) = 6

x, ln (2 x + 3) = 7

- 4 lo g_{9} (7 v) = 0

lo g_{2} (x) = lo g_{2} (- 8)

lo g_{10} (N) = - 0.488