What is the answer to log_{10}(N)=-0.488 ?

The answer to log_{10}(N)=-0.488 is N= 1/(10^{0.488)}

Solve for N: log_{10}(N)=-0.488

The solution is N= 1/(10^{0.488)}

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lo g_{10} (N) = - 0.488

N = \frac{1}{1 0 ^{0.488}}

Decimal Notation

N = 0.32508 \dots

Solution steps

lo g_{10} (N) = - 0.488

Apply log rules

N = \frac{1}{1 0 ^{0.488}}

- 8 lo g_{2} (x + 6) = - 5

2 lo g_{2} (x + 1) - lo g_{2} (x) = 2

lo g_{4} (X_{2}) = \frac{1}{2}

3 ln (x - 5) = 12

lo g_{X} (10) = \frac{2}{3}

What is the answer to log_{10}(N)=-0.488 ?
The answer to log_{10}(N)=-0.488 is N= 1/(10^{0.488)}
Solve for N: log_{10}(N)=-0.488
The solution is N= 1/(10^{0.488)}