What is the answer to log_{10}(a^{49})=2 ?

The answer to log_{10}(a^{49})=2 is a=10^{2/49}

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log_{10}(a^{49})=2

lo g_{10} (a^{49}) = 2

a = 1 0^{\frac{2}{49}}

Solution steps

lo g_{10} (a^{49}) = 2

Apply log rules

a = 1 0^{\frac{2}{49}}

Verify Solutions:

a = 1 0^{\frac{2}{49}}

True

The solution is

a = 1 0^{\frac{2}{49}}

lo g_{10} (x) + lo g_{10} (x + 8) = 2

lo g_{2} (\frac{40}{x}) = 3

lo g_{10} (x) = 2.10083394

lo g_{x} (4) = lo g_{2} (x)

5 lo g_{9} (a) = lo g_{9} (x)

What is the answer to log_{10}(a^{49})=2 ?
The answer to log_{10}(a^{49})=2 is a=10^{2/49}
Solve for a: log_{10}(a^{49})=2
The solution is a=10^{2/49}