What is the answer to 10*log_{10}(x^2)=2 ?

The answer to 10*log_{10}(x^2)=2 is x=sqrt(\sqrt[5]{10)},x=-sqrt(\sqrt[5]{10)}

Solve for x: 10*log_{10}(x^2)=2

The solution is x=sqrt(\sqrt[5]{10)},x=-sqrt(\sqrt[5]{10)}

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10 \cdot lo g_{10} (x^{2}) = 2

Solution steps

10 lo g_{10} (x^{2}) = 2

Divide both sides by

10

lo g_{10} (x^{2}) = \frac{1}{5}

Apply log rules

Solve

Verify Solutions:

True

The solutions are

- lo g_{10} (x) = 11.66

lo g_{x} (8) = 3

lo g_{32} (2) = lo g_{2} (x)

lo g_{10} (x) = 7.898888

lo g_{10} (X) = - 0.04

What is the answer to 10*log_{10}(x^2)=2 ?
The answer to 10*log_{10}(x^2)=2 is x=sqrt(\sqrt[5]{10)},x=-sqrt(\sqrt[5]{10)}
Solve for x: 10*log_{10}(x^2)=2
The solution is x=sqrt(\sqrt[5]{10)},x=-sqrt(\sqrt[5]{10)}