What is the answer to log_{32}(2)=log_{2}(x) ?

The answer to log_{32}(2)=log_{2}(x) is x=\sqrt[5]{2}

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log_{32}(2)=log_{2}(x)

lo g_{32} (2) = lo g_{2} (x)

Solution steps

lo g_{32} (2) = lo g_{2} (x)

Apply log rules

Switch sides

Verify Solutions:

True

The solution is

lo g_{10} (x) = 7.898888

lo g_{10} (X) = - 0.04

y, ln (m - y) = k t

lo g_{2} (x + 2) = - 2

ln (x + 1) = ln (x - 2) + ln (2)

What is the answer to log_{32}(2)=log_{2}(x) ?
The answer to log_{32}(2)=log_{2}(x) is x=\sqrt[5]{2}
Solve for x: log_{32}(2)=log_{2}(x)
The solution is x=\sqrt[5]{2}