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Popular >

solvefor y,ln(m-y)=kt

Solution

solve for

y, ln (m - y) = k t

Solution

y = - e^{k t} + m

Solution steps

ln (m - y) = k t

Apply log rules

m - y = e^{k t}

Solve

m - y = e^{k t} : y = - e^{k t} + m

y = - e^{k t} + m

Popular Examples

log_{2}(x+2)=-2

lo g_{2} (x + 2) = - 2

ln(x+1)=ln(x-2)+ln(2)

ln (x + 1) = ln (x - 2) + ln (2)

solvefor t,log_{r}(t)=p solve for

t, lo g_{r} (t) = p

log_{10}(x-3)=log_{10}(6)

lo g_{10} (x - 3) = lo g_{10} (6)

x - 4 = ln (x)

Frequently Asked Questions (FAQ)

What is the answer to solvefor y,ln(m-y)=kt ?
The answer to solvefor y,ln(m-y)=kt is y=-e^{kt}+m