What is the answer to x-4=ln(x) ?

The answer to x-4=ln(x) is x=-\W_{-1}(-1/(e^4)),x=-\W_{0}(-1/(e^4))

Solve for x: x-4=ln(x)

The solution is x=-\W_{-1}(-1/(e^4)),x=-\W_{0}(-1/(e^4))

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x - 4 = ln (x)

x = - W_{- 1} (- \frac{1}{e ^{4}}), x = - W_{0} (- \frac{1}{e ^{4}})

Solution steps

x - 4 = ln (x)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{x - 4} = e^{l n (x)}

Simplify

e^{l n (x)} : x

e^{x - 4} = x

Solve

e^{x - 4} = x : x = - W_{- 1} (- \frac{1}{e ^{4}}), x = - W_{0} (- \frac{1}{e ^{4}})

x = - W_{- 1} (- \frac{1}{e ^{4}}), x = - W_{0} (- \frac{1}{e ^{4}})

Verify Solutions:

x = - W_{- 1} (- \frac{1}{e ^{4}})

True

, x = - W_{0} (- \frac{1}{e ^{4}})

True

The solutions are

x = - W_{- 1} (- \frac{1}{e ^{4}}), x = - W_{0} (- \frac{1}{e ^{4}})

x, 2 z = lo g_{x} (y)

2 lo g_{2} (x + 3) = lo g_{2} (x + 5)

4 ln (4 b) - ln (2 b) = 0

- 0.3 = - 0.56585 - 0.059 ln (x)

lo g_{10} (36) + lo g_{10} (x) = 25

What is the answer to x-4=ln(x) ?
The answer to x-4=ln(x) is x=-\W_{-1}(-1/(e^4)),x=-\W_{0}(-1/(e^4))
Solve for x: x-4=ln(x)
The solution is x=-\W_{-1}(-1/(e^4)),x=-\W_{0}(-1/(e^4))