What is the answer to solvefor x,2z=log_{x}(y) ?

The answer to solvefor x,2z=log_{x}(y) is x=e^{(ln(y))/(2z)}

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solvefor x,2z=log_{x}(y)

solve for

x, 2 z = lo g_{x} (y)

x = e^{\frac{l n ( y )}{2 z}}

Solution steps

2 z = lo g_{x} (y)

Apply log rules

2 z = \frac{ln ( y )}{ln ( x )}

Multiply both sides by

ln (x)

2 z ln (x) = \frac{ln ( y )}{ln ( x )} ln (x)

Simplify

2 z ln (x) = ln (y)

Divide both sides by

2 z

ln (x) = \frac{ln ( y )}{2 z}

Apply log rules

x = e^{\frac{l n ( y )}{2 z}}

2 lo g_{2} (x + 3) = lo g_{2} (x + 5)

4 ln (4 b) - ln (2 b) = 0

- 0.3 = - 0.56585 - 0.059 ln (x)

lo g_{10} (36) + lo g_{10} (x) = 25

lo g_{2} (x + 2) = 35

What is the answer to solvefor x,2z=log_{x}(y) ?
The answer to solvefor x,2z=log_{x}(y) is x=e^{(ln(y))/(2z)}