What is the answer to (x+5)^2+3=(x-2)^2 ?

The answer to (x+5)^2+3=(x-2)^2 is x=-12/7

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(x+5)^2+3=(x-2)^2

(x + 5)^{2} + 3 = (x - 2)^{2}

x = - \frac{12}{7}

Solution steps

(x + 5)^{2} + 3 = (x - 2)^{2}

Expand

(x + 5)^{2} + 3 : x^{2} + 10 x + 28

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

x^{2} + 10 x + 28 = x^{2} - 4 x + 4

Move

28

to the right side

x^{2} + 10 x = x^{2} - 4 x - 24

Subtract

x^{2} - 4 x

from both sides

x^{2} + 10 x - (x^{2} - 4 x) = x^{2} - 4 x - 24 - (x^{2} - 4 x)

Simplify

14 x = - 24

Divide both sides by

14

x = - \frac{12}{7}

\frac{r}{3} - 9 \geq - 2

3 q^{2} + 2 q = 0

\frac{( 9 ^{- 2} )}{( 3 ^{- 3} )}

\frac{13}{15} - \frac{1}{2}

10 b - 30 a b^{2}

What is the answer to (x+5)^2+3=(x-2)^2 ?
The answer to (x+5)^2+3=(x-2)^2 is x=-12/7
Solve for x: (x+5)^2+3=(x-2)^2
The solution is x=-12/7