What is the answer to -2(log_{2}(x+1))=2 ?

The answer to -2(log_{2}(x+1))=2 is x=-1/2

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-2(log_{2}(x+1))=2

- 2 (lo g_{2} (x + 1)) = 2

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

- 2 (lo g_{2} (x + 1)) = 2

Divide both sides by

- 2

lo g_{2} (x + 1) = - 1

Apply log rules

x + 1 = \frac{1}{2}

Solve

x + 1 = \frac{1}{2} : x = - \frac{1}{2}

x = - \frac{1}{2}

Verify Solutions:

x = - \frac{1}{2}

True

The solution is

x = - \frac{1}{2}

lo g_{5} (x - 1) + 4 = 0

ln (k) = - 14.648

- 5.2 = lo g_{10} (x 0.0175)

ln (x + 1) - 1 = ln (x - 1)

lo g_{2} (x) lo g_{x} (3) = 3

What is the answer to -2(log_{2}(x+1))=2 ?
The answer to -2(log_{2}(x+1))=2 is x=-1/2
Solve for x: -2(log_{2}(x+1))=2
The solution is x=-1/2