What is the answer to ln(x+1)-1=ln(x-1) ?

The answer to ln(x+1)-1=ln(x-1) is x=(e+1)/(e-1)

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ln(x+1)-1=ln(x-1)

ln (x + 1) - 1 = ln (x - 1)

x = \frac{e + 1}{e - 1}

Decimal Notation

x = 2.16395 \dots

Solution steps

ln (x + 1) - 1 = ln (x - 1)

Apply log rules

x + 1 = (x - 1) e

Solve

x + 1 = (x - 1) e : x = \frac{e + 1}{e - 1}

x = \frac{e + 1}{e - 1}

Verify Solutions:

x = \frac{e + 1}{e - 1}

True

The solution is

x = \frac{e + 1}{e - 1}

lo g_{2} (x) lo g_{x} (3) = 3

2 lo g_{x} (12) = 1

2 ln (x + 1) = ln ((x + 1)^{22})

2 \cdot ln (x + 3) + 4 = x

lo g_{7} (2 x + 1) + lo g_{7} (x - 2) = 1

What is the answer to ln(x+1)-1=ln(x-1) ?
The answer to ln(x+1)-1=ln(x-1) is x=(e+1)/(e-1)
Solve for x: ln(x+1)-1=ln(x-1)
The solution is x=(e+1)/(e-1)