What is the answer to 2ln(x+1)=ln((x+1)^{22}) ?

The answer to 2ln(x+1)=ln((x+1)^{22}) is x=0

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2ln(x+1)=ln((x+1)^{22})

2 ln (x + 1) = ln ((x + 1)^{22})

x = 0

Solution steps

2 ln (x + 1) = ln ((x + 1)^{22})

Apply log rules

x + 1 = 1

Solve

x + 1 = 1 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

2 \cdot ln (x + 3) + 4 = x

lo g_{7} (2 x + 1) + lo g_{7} (x - 2) = 1

ln (x^{2} + 1) + 1 = ln (x + 1)

lo g_{3} (6 x + 5) = 2

lo g_{10} (4 x) + lo g_{10} (13) = 0

What is the answer to 2ln(x+1)=ln((x+1)^{22}) ?
The answer to 2ln(x+1)=ln((x+1)^{22}) is x=0
Solve for x: 2ln(x+1)=ln((x+1)^{22})
The solution is x=0