What is the answer to ln(x^2+1)+1=ln(x+1) ?

The answer to ln(x^2+1)+1=ln(x+1) is No Solution for x\in\mathbb{R}

Solve for x: ln(x^2+1)+1=ln(x+1)

The solution is No Solution for x\in\mathbb{R}

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ln (x^{2} + 1) + 1 = ln (x + 1)

No Solution for x \in R

Solution steps

ln (x^{2} + 1) + 1 = ln (x + 1)

Apply log rules

(x^{2} + 1) e = x + 1

Solve

(x^{2} + 1) e = x + 1 :

No Solution for

x \in R

No Solution for x \in R

lo g_{3} (6 x + 5) = 2

lo g_{10} (4 x) + lo g_{10} (13) = 0

y, x = - lo g_{e} (y)

ln (2 x - 1) = ln (3 x)

lo g_{10} (x) = 699

What is the answer to ln(x^2+1)+1=ln(x+1) ?
The answer to ln(x^2+1)+1=ln(x+1) is No Solution for x\in\mathbb{R}
Solve for x: ln(x^2+1)+1=ln(x+1)
The solution is No Solution for x\in\mathbb{R}