What is the answer to 3log_{2}(x-5)-3=12 ?

The answer to 3log_{2}(x-5)-3=12 is x=37

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3log_{2}(x-5)-3=12

3 lo g_{2} (x - 5) - 3 = 12

x = 37

Solution steps

3 lo g_{2} (x - 5) - 3 = 12

Move

3

to the right side

3 lo g_{2} (x - 5) = 15

Divide both sides by

3

lo g_{2} (x - 5) = 5

Apply log rules

x - 5 = 32

Solve

x - 5 = 32 : x = 37

x = 37

Verify Solutions:

x = 37

True

The solution is

x = 37

x, 6 ln (7 x - 2) - 4 = 20

lo g_{4} (x) = lo g_{2} (3)

lo g_{4} (n) = \frac{5}{2}

\frac{1}{2} x - 3 = ln (x) - 1

y, ln (y + 3) = 2 ln (x)

What is the answer to 3log_{2}(x-5)-3=12 ?
The answer to 3log_{2}(x-5)-3=12 is x=37
Solve for x: 3log_{2}(x-5)-3=12
The solution is x=37