What is the answer to solvefor y,ln(y+3)=2ln(x) ?

The answer to solvefor y,ln(y+3)=2ln(x) is y=x^2-3 {x>0}

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solvefor y,ln(y+3)=2ln(x)

solve for

y, ln (y + 3) = 2 ln (x)

y = x^{2} - 3 {x > 0}

Solution steps

ln (y + 3) = 2 ln (x)

Apply log rules

y + 3 = x^{2}

Solve

y + 3 = x^{2} : y = x^{2} - 3

y = x^{2} - 3

Verify Solutions:

y = x^{2} - 3 {x > 0}

The solution is

y = x^{2} - 3 {x > 0}

x \cdot 9^{l o g_{3} (x)} = 27

9 ln (0.25 x) = 15

1 = lo g_{6} (- 7 + 2 x)

3 lo g_{4} (x) = 12

8.79 = - lo g_{10} (x)

What is the answer to solvefor y,ln(y+3)=2ln(x) ?
The answer to solvefor y,ln(y+3)=2ln(x) is y=x^2-3 {x>0}