What is the answer to 1=log_{6}(-7+2x) ?

The answer to 1=log_{6}(-7+2x) is x= 13/2

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1=log_{6}(-7+2x)

1 = lo g_{6} (- 7 + 2 x)

x = \frac{13}{2}

Decimal Notation

x = 6.5

Solution steps

1 = lo g_{6} (- 7 + 2 x)

Apply log rules

6 = - 7 + 2 x

Solve

6 = - 7 + 2 x : x = \frac{13}{2}

x = \frac{13}{2}

3 lo g_{4} (x) = 12

8.79 = - lo g_{10} (x)

y, x = lo g_{3} (y + 1)

x, lo g_{10} (x) = - 5

ln (4 x) = ln (2) + 6 ln (x)

What is the answer to 1=log_{6}(-7+2x) ?
The answer to 1=log_{6}(-7+2x) is x= 13/2
Solve for x: 1=log_{6}(-7+2x)
The solution is x= 13/2