What is the answer to solvefor y,x=log_{3}(y+1) ?

The answer to solvefor y,x=log_{3}(y+1) is y=3^x-1

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solvefor y,x=log_{3}(y+1)

solve for

y, x = lo g_{3} (y + 1)

y = 3^{x} - 1

Solution steps

x = lo g_{3} (y + 1)

Apply log rules

3^{x} = y + 1

Solve

3^{x} = y + 1 : y = 3^{x} - 1

y = 3^{x} - 1

x, lo g_{10} (x) = - 5

ln (4 x) = ln (2) + 6 ln (x)

x, ln (y) + ln (x) = k

2 + lo g_{3} (3 x + 5) = 4

lo g_{10} (x) = 6.1

What is the answer to solvefor y,x=log_{3}(y+1) ?
The answer to solvefor y,x=log_{3}(y+1) is y=3^x-1