What is the answer to 5log_{10}(2x-8)=2 ?

The answer to 5log_{10}(2x-8)=2 is x=(10^{2/5}+8)/2

Solve for x: 5log_{10}(2x-8)=2

The solution is x=(10^{2/5}+8)/2

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5 lo g_{10} (2 x - 8) = 2

x = \frac{1 0 ^{\frac{2}{5}} + 8}{2}

Decimal Notation

x = 5.25594 \dots

Solution steps

5 lo g_{10} (2 x - 8) = 2

Divide both sides by

5

lo g_{10} (2 x - 8) = \frac{2}{5}

Apply log rules

2 x - 8 = 1 0^{\frac{2}{5}}

Solve

2 x - 8 = 1 0^{\frac{2}{5}} : x = \frac{1 0 ^{\frac{2}{5}} + 8}{2}

x = \frac{1 0 ^{\frac{2}{5}} + 8}{2}

Verify Solutions:

x = \frac{1 0 ^{\frac{2}{5}} + 8}{2}

True

The solution is

x = \frac{1 0 ^{\frac{2}{5}} + 8}{2}

10 lo g_{10} (1 + x^{2}) = 0.5

ln (s) = 74484

lo g_{10} (N) = 2

y, x = lo g_{2} (2 y + 1)

ln (- 4 x + 5) - 5 = - 7

What is the answer to 5log_{10}(2x-8)=2 ?
The answer to 5log_{10}(2x-8)=2 is x=(10^{2/5}+8)/2
Solve for x: 5log_{10}(2x-8)=2
The solution is x=(10^{2/5}+8)/2