What is the answer to -ln(x)=2.32 ?

The answer to -ln(x)=2.32 is x= 1/(e^{2.32)}

Solve for x: -ln(x)=2.32

The solution is x= 1/(e^{2.32)}

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- ln (x) = 2.32

x = \frac{1}{e ^{2.32}}

Decimal Notation

x = 0.09827 \dots

Solution steps

- ln (x) = 2.32

Divide both sides by

- 1

ln (x) = - 2.32

Apply log rules

x = \frac{1}{e ^{2.32}}

Verify Solutions:

x = \frac{1}{e ^{2.32}}

True

The solution is

x = \frac{1}{e ^{2.32}}

- ln (x) = 2.38

lo g_{2} (x) = 8.16

0 = 0.6552 ln (x) + 948 - 0.1 x + 0.2

x, 4 = lo g_{3} (x)

0 = b lo g_{c} (a x)

What is the answer to -ln(x)=2.32 ?
The answer to -ln(x)=2.32 is x= 1/(e^{2.32)}
Solve for x: -ln(x)=2.32
The solution is x= 1/(e^{2.32)}