What is the answer to log_{a}(y)+log_{a}(5)=7 ?

The answer to log_{a}(y)+log_{a}(5)=7 is y= 1/5 a^7 {0 1}

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log_{a}(y)+log_{a}(5)=7

lo g_{a} (y) + lo g_{a} (5) = 7

y = \frac{1}{5} a^{7} {0 < a < 1 or a > 1}

Solution steps

lo g_{a} (y) + lo g_{a} (5) = 7

Move

lo g_{a} (5)

to the right side

lo g_{a} (y) = 7 - lo g_{a} (5)

Apply log rules

y = \frac{1}{5} a^{7}

Verify Solutions:

y = \frac{1}{5} a^{7} {0 < a < 1 or a > 1}

The solution is

y = \frac{1}{5} a^{7} {0 < a < 1 or a > 1}

lo g_{10} (4 x + 8) = 2 + lo g_{10} (3)

ln (3) + ln (6 - x) = 2 ln (x)

0 = \frac{1 - 3 ln ( x )}{x ^{3}}

a = 20 lo g_{10} (x)

lo g_{10} (1 - 3 x) = 2

What is the answer to log_{a}(y)+log_{a}(5)=7 ?
The answer to log_{a}(y)+log_{a}(5)=7 is y= 1/5 a^7 {0<a<1\lor a>1}