What is the answer to log_{4}(x+3)-log_{4}(x)=3 ?

The answer to log_{4}(x+3)-log_{4}(x)=3 is x= 1/21

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log_{4}(x+3)-log_{4}(x)=3

lo g_{4} (x + 3) - lo g_{4} (x) = 3

x = \frac{1}{21}

Decimal Notation

x = 0.04761 \dots

Solution steps

lo g_{4} (x + 3) - lo g_{4} (x) = 3

Add

lo g_{4} (x)

to both sides

lo g_{4} (x + 3) - lo g_{4} (x) + lo g_{4} (x) = 3 + lo g_{4} (x)

Simplify

lo g_{4} (x + 3) = 3 + lo g_{4} (x)

Apply log rules

x + 3 = 64 x

Solve

x + 3 = 64 x : x = \frac{1}{21}

x = \frac{1}{21}

Verify Solutions:

x = \frac{1}{21}

True

The solution is

x = \frac{1}{21}

lo g_{4} (x + 3) - lo g_{4} (x) = 1

y, d = ln (\frac{x}{y})

n, 0 = lo g_{9} (x^{n})

ln (x) + 2 ln (4 x) = ln (6192)

3 ln (7 x - 1) + 4 = 7

What is the answer to log_{4}(x+3)-log_{4}(x)=3 ?
The answer to log_{4}(x+3)-log_{4}(x)=3 is x= 1/21
Solve for x: log_{4}(x+3)-log_{4}(x)=3
The solution is x= 1/21