What is the answer to -3=20log_{10}(2x) ?

The answer to -3=20log_{10}(2x) is x= 1/(2*10^{3/20)}

Solve for x: -3=20log_{10}(2x)

The solution is x= 1/(2*10^{3/20)}

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- 3 = 20 lo g_{10} (2 x)

x = \frac{1}{2 \cdot 1 0 ^{\frac{3}{20}}}

Decimal Notation

x = 0.35397 \dots

Solution steps

- 3 = 20 lo g_{10} (2 x)

Switch sides

20 lo g_{10} (2 x) = - 3

Divide both sides by

20

lo g_{10} (2 x) = - \frac{3}{20}

Apply log rules

2 x = \frac{1}{1 0 ^{\frac{3}{20}}}

Solve

2 x = \frac{1}{1 0 ^{\frac{3}{20}}} : x = \frac{1}{2 \cdot 1 0 ^{\frac{3}{20}}}

x = \frac{1}{2 \cdot 1 0 ^{\frac{3}{20}}}

Verify Solutions:

x = \frac{1}{2 \cdot 1 0 ^{\frac{3}{20}}}

True

The solution is

x = \frac{1}{2 \cdot 1 0 ^{\frac{3}{20}}}

5 ln (4 x + 3) - 1 = 19

lo g_{10} (p^{- 5}) = 16

lo g_{10} (9 - 5 x) = - 1

ln (2 x^{2} - 3) = ln (9 x - 13)

ln (x) = \frac{1}{4 e ^{2}}

What is the answer to -3=20log_{10}(2x) ?
The answer to -3=20log_{10}(2x) is x= 1/(2*10^{3/20)}
Solve for x: -3=20log_{10}(2x)
The solution is x= 1/(2*10^{3/20)}