What is the answer to log_{2}((m-6)(m+1))=3 ?

The answer to log_{2}((m-6)(m+1))=3 is m=7,m=-2

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log_{2}((m-6)(m+1))=3

lo g_{2} ((m - 6) (m + 1)) = 3

m = 7, m = - 2

Solution steps

lo g_{2} ((m - 6) (m + 1)) = 3

Apply log rules

(m - 6) (m + 1) = 8

Solve

(m - 6) (m + 1) = 8 : m = 7, m = - 2

m = 7, m = - 2

lo g_{10} (x^{2} + 1) = - 0.7

5.56 = ln (\frac{x}{100})

lo g_{10} (x - 2) = \frac{11}{5}

lo g_{7} (\frac{3 x + 2}{x - 2}) = 1

lo g_{3} (6 x - 9) = 4

What is the answer to log_{2}((m-6)(m+1))=3 ?
The answer to log_{2}((m-6)(m+1))=3 is m=7,m=-2
Solve for m: log_{2}((m-6)(m+1))=3
The solution is m=7,m=-2