What is the answer to (alog_{10}(x)1)/(16)=-4 ?

The answer to (alog_{10}(x)1)/(16)=-4 is x=10^{-(64)/a}

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(alog_{10}(x)1)/(16)=-4

\frac{a lo g _{10} ( x ) 1}{16} = - 4

x = 1 0^{- \frac{64}{a}}

Solution steps

\frac{a lo g _{10} ( x ) \cdot 1}{16} = - 4

Multiply both sides by

16

a lo g_{10} (x) = - 64

Divide both sides by

a

lo g_{10} (x) = - \frac{64}{a}

Apply log rules

x = 1 0^{- \frac{64}{a}}

Verify Solutions:

x = 1 0^{- \frac{64}{a}}

True

The solution is

x = 1 0^{- \frac{64}{a}}

lo g_{10} (2 x) + 2 lo g_{10} (x) = 4

lo g_{10} (5 x - 10) = 5

P, lo g_{10} (P^{- 1}) = n

3 lo g_{3} (x - 5) = 3

2 ln (x^{3}) - 3 ln (x^{2}) = 0

What is the answer to (alog_{10}(x)1)/(16)=-4 ?
The answer to (alog_{10}(x)1)/(16)=-4 is x=10^{-(64)/a}