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Popular >

ln(4^x)=ln(e^{5x-1})

Solution

ln (4^{x}) = ln (e^{5 x - 1})

Solution

x = \frac{1}{- 2 ln ( 2 ) + 5}

+1

Decimal Notation

x = 0.27672 \dots

Solution steps

ln (4^{x}) = ln (e^{5 x - 1})

Apply log rules

4^{x} = e^{5 x - 1}

Solve

4^{x} = e^{5 x - 1} : x = \frac{1}{- 2 ln ( 2 ) + 5}

x = \frac{1}{- 2 ln ( 2 ) + 5}

Verify Solutions:

x = \frac{1}{- 2 ln ( 2 ) + 5}

True

The solution is

x = \frac{1}{- 2 ln ( 2 ) + 5}

Popular Examples

log_{2}(3-x)+log_{2}(7-x)=5

lo g_{2} (3 - x) + lo g_{2} (7 - x) = 5

log_{2}(2x+6)=3

lo g_{2} (2 x + 6) = 3

2+2ln(x)=ln(x)+ln(2)

2 + 2 ln (x) = ln (x) + ln (2)

9=9.6+log_{10}(x)

9 = 9.6 + lo g_{10} (x)

log_{2}(x+2)=log_{2}(3x)

lo g_{2} (x + 2) = lo g_{2} (3 x)

Frequently Asked Questions (FAQ)

What is the answer to ln(4^x)=ln(e^{5x-1}) ?
The answer to ln(4^x)=ln(e^{5x-1}) is x= 1/(-2ln(2)+5)