What is the answer to solvefor x,ln(y)=x+ln(x-5)+c ?

The answer to solvefor x,ln(y)=x+ln(x-5)+c is x=\W(y/(e^{c+5)})+5

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solvefor x,ln(y)=x+ln(x-5)+c

solve for

x, ln (y) = x + ln (x - 5) + c

x = W (\frac{y}{e ^{c + 5}}) + 5

Solution steps

ln (y) = x + ln (x - 5) + c

Switch sides

x + ln (x - 5) + c = ln (y)

Move

x

to the right side

ln (x - 5) + c = ln (y) - x

Move

c

to the right side

ln (x - 5) = ln (y) - x - c

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x - 5)} = e^{l n (y) - x - c}

Simplify

e^{l n (x - 5)} : x - 5

Simplify

e^{l n (y) - x - c} : e^{- x - c} y

x - 5 = e^{- x - c} y

Solve

x - 5 = e^{- x - c} y : x = W (\frac{y}{e ^{c + 5}}) + 5

x = W (\frac{y}{e ^{c + 5}}) + 5

lo g_{5} (1 lo g_{3} (x)) = 0

ln (x) = ln (x - 1) + 1

2 lo g_{3} (6) - 2 lo g_{3} (x) = 9

lo g_{5} (x - 8) - lo g_{5} (x - 4) = 1

lo g_{10} (x^{2}) + 7 x = 1

What is the answer to solvefor x,ln(y)=x+ln(x-5)+c ?
The answer to solvefor x,ln(y)=x+ln(x-5)+c is x=\W(y/(e^{c+5)})+5