What is the answer to 2log_{3}(6)-2log_{3}(x)=9 ?

The answer to 2log_{3}(6)-2log_{3}(x)=9 is x= 1/(3^{(9-2log_{3)(6))/2}}

Solve for x: 2log_{3}(6)-2log_{3}(x)=9

The solution is x= 1/(3^{(9-2log_{3)(6))/2}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 lo g_{3} (6) - 2 lo g_{3} (x) = 9

x = \frac{1}{3 ^{\frac{9 - 2 l o g _{3} ( 6 )}{2}}}

Decimal Notation

x = 0.04276 \dots

Solution steps

2 lo g_{3} (6) - 2 lo g_{3} (x) = 9

Move

2 lo g_{3} (6)

to the right side

- 2 lo g_{3} (x) = 9 - 2 lo g_{3} (6)

Divide both sides by

- 2

lo g_{3} (x) = - \frac{9 - 2 lo g _{3} ( 6 )}{2}

Apply log rules

x = \frac{1}{3 ^{\frac{9 - 2 l o g _{3} ( 6 )}{2}}}

Verify Solutions:

x = \frac{1}{3 ^{\frac{9 - 2 l o g _{3} ( 6 )}{2}}}

True

The solution is

x = \frac{1}{3 ^{\frac{9 - 2 l o g _{3} ( 6 )}{2}}}

lo g_{5} (x - 8) - lo g_{5} (x - 4) = 1

lo g_{10} (x^{2}) + 7 x = 1

3 lo g_{2} (x) - 1 = lo g_{2} (27)

lo g_{16} (x) = lo g_{4} (x^{2})

ln (x (x - 1)) = ln (x) + ln (x - 1)

What is the answer to 2log_{3}(6)-2log_{3}(x)=9 ?
The answer to 2log_{3}(6)-2log_{3}(x)=9 is x= 1/(3^{(9-2log_{3)(6))/2}}
Solve for x: 2log_{3}(6)-2log_{3}(x)=9
The solution is x= 1/(3^{(9-2log_{3)(6))/2}}