What is the answer to ln(x(x-1))=ln(x)+ln(x-1) ?

The answer to ln(x(x-1))=ln(x)+ln(x-1) is x>1

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ln(x(x-1))=ln(x)+ln(x-1)

ln (x (x - 1)) = ln (x) + ln (x - 1)

x > 1

Solution steps

ln (x (x - 1)) = ln (x) + ln (x - 1)

Apply log rules

x (x - 1) = x (x - 1)

Both sides are equal

True for all x

Verify Solutions:

x > 1

The solution is

x > 1

lo g_{10} (2 x - 5) = - 1

lo g_{9} (4 x + 4) = 2

lo g_{2} (x) - 1 = 3

x, y^{2} = ln (x y)

0.78175 = 0.6446 ln (x) - 0.5557

What is the answer to ln(x(x-1))=ln(x)+ln(x-1) ?
The answer to ln(x(x-1))=ln(x)+ln(x-1) is x>1
Solve for x: ln(x(x-1))=ln(x)+ln(x-1)
The solution is x>1