What is the answer to 2log_{3}(6)+log_{3}(y)=4 ?

The answer to 2log_{3}(6)+log_{3}(y)=4 is y= 9/4

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2log_{3}(6)+log_{3}(y)=4

2 lo g_{3} (6) + lo g_{3} (y) = 4

y = \frac{9}{4}

Decimal Notation

y = 2.25

Solution steps

2 lo g_{3} (6) + lo g_{3} (y) = 4

Move

2 lo g_{3} (6)

to the right side

lo g_{3} (y) = 4 - 2 lo g_{3} (6)

Apply log rules

y = \frac{9}{4}

Verify Solutions:

y = \frac{9}{4}

True

The solution is

y = \frac{9}{4}

ln (x + 1) - ln (3) = 3

lo g_{6} (- x^{2} + 12 x) = 2

3 ln (x - 6) = 15

x = 7 lo g_{x} (e)

y, ln (y^{2}) = z

What is the answer to 2log_{3}(6)+log_{3}(y)=4 ?
The answer to 2log_{3}(6)+log_{3}(y)=4 is y= 9/4
Solve for y: 2log_{3}(6)+log_{3}(y)=4
The solution is y= 9/4