What is the answer to solvefor y,ln(y^2)=z ?

The answer to solvefor y,ln(y^2)=z is y=sqrt(e^z),y=-sqrt(e^z)

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solvefor y,ln(y^2)=z

solve for

y, ln (y^{2}) = z

y = e^{z}, y = - e^{z}

Solution steps

ln (y^{2}) = z

Apply log rules

y^{2} = e^{z}

Solve

y^{2} = e^{z} : y = e^{z}, y = - e^{z}

y = e^{z}, y = - e^{z}

lo g_{8} (8 x^{2}) = 1

1 + \frac{1}{x} + ln (x) = 0

y, ln (y - 14) = x + ln (x)

lo g_{5} (x^{2}) + 9 = 2

lo g_{6} (3 x) - lo g_{6} (2 x) + 4 = 0

What is the answer to solvefor y,ln(y^2)=z ?
The answer to solvefor y,ln(y^2)=z is y=sqrt(e^z),y=-sqrt(e^z)