What is the answer to 1+1/x+ln(x)=0 ?

The answer to 1+1/x+ln(x)=0 is No Solution for x\in\mathbb{R}

Solve for x: 1+1/x+ln(x)=0

The solution is No Solution for x\in\mathbb{R}

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1 + \frac{1}{x} + ln (x) = 0

No Solution for x \in R

Solution steps

1 + \frac{1}{x} + ln (x) = 0

Move

\frac{1}{x}

to the right side

1 + ln (x) = - \frac{1}{x}

Move

1

to the right side

ln (x) = - \frac{1}{x} - 1

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{- \frac{1}{x} - 1}

Simplify

e^{l n (x)} : x

x = e^{- \frac{1}{x} - 1}

Solve

x = e^{- \frac{1}{x} - 1} :

No Solution for

x \in R

No Solution for x \in R

y, ln (y - 14) = x + ln (x)

lo g_{5} (x^{2}) + 9 = 2

lo g_{6} (3 x) - lo g_{6} (2 x) + 4 = 0

3 ln (x - 6) = - 3

lo g_{4} (x - 3) = 1

What is the answer to 1+1/x+ln(x)=0 ?
The answer to 1+1/x+ln(x)=0 is No Solution for x\in\mathbb{R}
Solve for x: 1+1/x+ln(x)=0
The solution is No Solution for x\in\mathbb{R}