What is the answer to ln((2x-3)/(x+1))=e ?

The answer to ln((2x-3)/(x+1))=e is x=(e^e+3)/(2-e^e)

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ln((2x-3)/(x+1))=e

ln (\frac{2 x - 3}{x + 1}) = e

x = \frac{e ^{e} + 3}{2 - e ^{e}}

Decimal Notation

x = - 1.38010 \dots

Solution steps

ln (\frac{2 x - 3}{x + 1}) = e

Apply log rules

\frac{2 x - 3}{x + 1} = e^{e}

Multiply both sides by

x + 1

\frac{2 x - 3}{x + 1} (x + 1) = e^{e} (x + 1)

Simplify

2 x - 3 = e^{e} (x + 1)

Solve

2 x - 3 = e^{e} (x + 1) : x = \frac{e ^{e} + 3}{2 - e ^{e}}

x = \frac{e ^{e} + 3}{2 - e ^{e}}

Verify Solutions:

x = \frac{e ^{e} + 3}{2 - e ^{e}}

True

The solution is

x = \frac{e ^{e} + 3}{2 - e ^{e}}

- 0.2 X + lo g_{10} (X) = - 3.2325

lo g_{10} (X + 2 (X + 5)) = 1

lo g_{2} (5) + lo g_{2} (x - 2) = 1

10 \cdot lo g_{10} (x) = 3

0.35 = ln (y)

What is the answer to ln((2x-3)/(x+1))=e ?
The answer to ln((2x-3)/(x+1))=e is x=(e^e+3)/(2-e^e)