What is the answer to x^2-y^2+i2xy=y+ix ?

The answer to x^2-y^2+i2xy=y+ix is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-y^2+i2xy=y+ix

x^{2} - y^{2} + i 2 x y = y + i x

x = 0, x = 0, x = \frac{3}{2}, x = - \frac{3}{2}, y = - 1 y = 0 y = \frac{1}{2} y = \frac{1}{2}

Solution steps

x^{2} - y^{2} + i 2 x y = y + i x

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x^{2} - y^{2} = y 2 x y = x]

[x^{2} - y^{2} = y 2 x y = x] : x = 0, x = 0, x = \frac{3}{2}, x = - \frac{3}{2}, y = - 1 y = 0 y = \frac{1}{2} y = \frac{1}{2}

x = 0, x = 0, x = \frac{3}{2}, x = - \frac{3}{2}, y = - 1 y = 0 y = \frac{1}{2} y = \frac{1}{2}

\frac{- 4 + x i}{2 - 3 i} = y - 2 i

3 x - 2 i y - i x + 5 y = 7 + 5 i

x + i y = ∣ x - i y ∣

\frac{4 + x i}{2 + i} = y + 2 i

(a - 1) + (b + 3) i = 5 + 8 i