What is the answer to (1+i)(x+2y)-(3-2i)(x-y)=8+3i ?

The answer to (1+i)(x+2y)-(3-2i)(x-y)=8+3i is x=1,y=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1+i)(x+2y)-(3-2i)(x-y)=8+3i

(1 + i) (x + 2 y) - (3 - 2 i) (x - y) = 8 + 3 i

x = 1, y = 2

Solution steps

(1 + i) (x + 2 y) - (3 - 2 i) (x - y) = 8 + 3 i

Rewrite

(1 + i) (x + 2 y) - (3 - 2 i) (x - y)

in standard complex form:

(- 2 x + 5 y) + 3 x i

(- 2 x + 5 y) + 3 x i = 8 + 3 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- 2 x + 5 y = 8 3 x = 3]

[- 2 x + 5 y = 8 3 x = 3] : x = 1, y = 2

x = 1, y = 2

x + y i = 2

(x + y i) (1 + 2 i) = - 1 + 8 i

\frac{2 - i}{z - 1} = 1 + 2 i

5 x + 6 i = - 20 + 2

x^{2} - 3 i x + (- 3 + i) = 0

What is the answer to (1+i)(x+2y)-(3-2i)(x-y)=8+3i ?
The answer to (1+i)(x+2y)-(3-2i)(x-y)=8+3i is x=1,y=2