What is the answer to -340i=X(10-159i)-Y(-159i) ?

The answer to -340i=X(10-159i)-Y(-159i) is X=0,Y=-340/159

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-340i=X(10-159i)-Y(-159i)

- 340 i = X (10 - 159 i) - Y (- 159 i)

X = 0, Y = - \frac{340}{159}

Solution steps

- 340 i = X (10 - 159 i) - Y (- 159 i)

Rewrite

- 340 i

in standard complex form:

0 - 340 i

0 - 340 i = X (10 - 159 i) - Y (- 159 i)

Rewrite

X (10 - 159 i) - Y (- 159 i)

in standard complex form:

10 X + (- 159 X + 159 Y) i

0 - 340 i = 10 X + (- 159 X + 159 Y) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[0 = 10 X - 340 = - 159 X + 159 Y]

[0 = 10 X - 340 = - 159 X + 159 Y] : X = 0, Y = - \frac{340}{159}

X = 0, Y = - \frac{340}{159}

7 x + 2 y - 2 i = 3 + (3 x + \frac{1}{5} y) i

ai + b + 4 = bi - 2 i + 3 a

z^{2} = 8 + 6 i

(2 x - 3 y - 5) + i (x + 2 y + 1) = 0

5 x + 12 y i = - 10 + 4 i

What is the answer to -340i=X(10-159i)-Y(-159i) ?
The answer to -340i=X(10-159i)-Y(-159i) is X=0,Y=-340/159