What is the answer to (-1+2i)/(8i)=a+bi ?

The answer to (-1+2i)/(8i)=a+bi is a= 1/4 ,b= 1/8

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(-1+2i)/(8i)=a+bi

\frac{- 1 + 2 i}{8 i} = a + bi

a = \frac{1}{4}, b = \frac{1}{8}

Solution steps

\frac{- 1 + 2 i}{8 i} = a + bi

Expand

\frac{- 1 + 2 i}{8 i} : \frac{1}{4} + \frac{i}{8}

\frac{1}{4} + \frac{i}{8} = a + bi

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[\frac{1}{4} = a \frac{1}{8} = b]

[\frac{1}{4} = a \frac{1}{8} = b] : a = \frac{1}{4}, b = \frac{1}{8}

a = \frac{1}{4}, b = \frac{1}{8}

z^{2} - 8 z + 18 = 8 i

(- 1 + i) x + (1 + i 2) y = 1

z^{2} + z = 5 + 5 i

z, z - \frac{1}{z} = 5 + 4 i

x^{2} + (1 - i) x + i = 0

What is the answer to (-1+2i)/(8i)=a+bi ?
The answer to (-1+2i)/(8i)=a+bi is a= 1/4 ,b= 1/8