What is the answer to (1+i)x-(1-2i)y=1+4i ?

The answer to (1+i)x-(1-2i)y=1+4i is x=2,y=1

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(1+i)x-(1-2i)y=1+4i

(1 + i) x - (1 - 2 i) y = 1 + 4 i

x = 2, y = 1

Solution steps

(1 + i) x - (1 - 2 i) y = 1 + 4 i

Rewrite

(1 + i) x - (1 - 2 i) y

in standard complex form:

(x - y) + (x + 2 y) i

(x - y) + (x + 2 y) i = 1 + 4 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x - y = 1 x + 2 y = 4]

[x - y = 1 x + 2 y = 4] : x = 2, y = 1

x = 2, y = 1

z^{2} + z + 1 - i = 0

x + 2 + 3 y i = - 4 x + (y + 4) i

(2 + i) x - y = 0

i z^{2} + 2 z = z + i

(x^{2} - 9) + (2 y - 5) i = 7 i

What is the answer to (1+i)x-(1-2i)y=1+4i ?
The answer to (1+i)x-(1-2i)y=1+4i is x=2,y=1