What is the answer to 3x+(y-2)i=(5-2x)+(3y-8)i ?

The answer to 3x+(y-2)i=(5-2x)+(3y-8)i is x=1,y=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x+(y-2)i=(5-2x)+(3y-8)i

3 x + (y - 2) i = (5 - 2 x) + (3 y - 8) i

x = 1, y = 3

Solution steps

3 x + (y - 2) i = (5 - 2 x) + (3 y - 8) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 x = 5 - 2 x y - 2 = 3 y - 8]

[3 x = 5 - 2 x y - 2 = 3 y - 8] : x = 1, y = 3

x = 1, y = 3

+ 28 + 2 i + z^{2} = 30 - 2 i, z^{1} = 3

(5 x - 2 y) + (8 x + 10 y) i = 38 + 8 i

- (b + 2) i - 8 + a = b - 2 + (3 b - 6) i

3 x - y = i + 2 i x - i y

x + y + (2 x - y) i = 1 + i

What is the answer to 3x+(y-2)i=(5-2x)+(3y-8)i ?
The answer to 3x+(y-2)i=(5-2x)+(3y-8)i is x=1,y=3