What is the answer to 1-2sqrt(7)k_{1}i-8k_{2}=0 ?

The answer to 1-2sqrt(7)k_{1}i-8k_{2}=0 is k_{2}= 1/8 ,k_{1}=0

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1-2sqrt(7)k_{1}i-8k_{2}=0

1 - 27 k_{1} i - 8 k_{2} = 0

k_{2} = \frac{1}{8}, k_{1} = 0

Solution steps

1 - 27 k_{1} i - 8 k_{2} = 0

Rewrite

1 - 27 k_{1} i - 8 k_{2}

in standard complex form:

(1 - 8 k_{2}) - 27 k_{1} i

(1 - 8 k_{2}) - 27 k_{1} i = 0

Rewrite

0

in standard complex form:

0 + 0 i

(1 - 8 k_{2}) - 27 k_{1} i = 0 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[1 - 8 k_{2} = 0 - 27 k_{1} = 0]

[1 - 8 k_{2} = 0 - 27 k_{1} = 0] : k_{2} = \frac{1}{8}, k_{1} = 0

k_{2} = \frac{1}{8}, k_{1} = 0

z^{2} - (2 + i) \cdot z + (- 1 + 7 i) = 0

z, z^{2} = 1 + i

x i (x + 3 y) = (1 + y i) (3 x + 4 i)

x^{2} - 3 - 3 i = 0

3 x^{2} + 6 i x = 0

What is the answer to 1-2sqrt(7)k_{1}i-8k_{2}=0 ?
The answer to 1-2sqrt(7)k_{1}i-8k_{2}=0 is k_{2}= 1/8 ,k_{1}=0