What is the answer to 1/2-(y-4)i=(x+1)+2i ?

The answer to 1/2-(y-4)i=(x+1)+2i is x=-1/2 ,y=2

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1/2-(y-4)i=(x+1)+2i

\frac{1}{2} - (y - 4) i = (x + 1) + 2 i

x = - \frac{1}{2}, y = 2

Solution steps

\frac{1}{2} - (y - 4) i = (x + 1) + 2 i

Rewrite

\frac{1}{2} - (y - 4) i

in standard complex form:

\frac{1}{2} + (- y + 4) i

\frac{1}{2} + (- y + 4) i = (x + 1) + 2 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[\frac{1}{2} = x + 1 - y + 4 = 2]

[\frac{1}{2} = x + 1 - y + 4 = 2] : x = - \frac{1}{2}, y = 2

x = - \frac{1}{2}, y = 2

z = 5 i^{131} + 3 i^{127} - 8^{343}

z^{2} + (1 + i) z + 1 = 0

3 i = a + bi

i (x) = \frac{- 4}{5 x + 7}

\frac{1}{z} = i

What is the answer to 1/2-(y-4)i=(x+1)+2i ?
The answer to 1/2-(y-4)i=(x+1)+2i is x=-1/2 ,y=2