What is the answer to p=4piir^2 ?

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p=4piir^2

p = 4 πi r^{2}

(p = 0, r = 0)

Solution steps

p = 4 πi r^{2}

Rewrite

p

in standard complex form:

p + 0 i

p + 0 i = 4 πi r^{2}

Rewrite

4 πi r^{2}

in standard complex form:

0 + 4 π r^{2} i

p + 0 i = 0 + 4 π r^{2} i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[p = 0 0 = 4 π r^{2}]

[p = 0 0 = 4 π r^{2}] : (p = 0, r = 0)

(p = 0, r = 0)

z^{2} = - 3 - i

(x - 1) i + (y + 1) = (1 + i) (4 - 3 i)

3 x - 5 i = 6 - (10 y) i

z^{2} + z + 2 + i = 0

i zz = 7 + 4 i