What is the answer to (a+b+3)+(8+b)i=2a+(3a-b)i ?

The answer to (a+b+3)+(8+b)i=2a+(3a-b)i is a=2,b=-1

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(a+b+3)+(8+b)i=2a+(3a-b)i

(a + b + 3) + (8 + b) i = 2 a + (3 a - b) i

a = 2, b = - 1

Solution steps

(a + b + 3) + (8 + b) i = 2 a + (3 a - b) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[a + b + 3 = 2 a 8 + b = 3 a - b]

[a + b + 3 = 2 a 8 + b = 3 a - b] : a = 2, b = - 1

a = 2, b = - 1

(x + 1) + 6 y i = 4 + 24 i

s i \frac{159}{100} = a, b c

6 i - 2 j = a (i - j) + b (i + j)

z, ba rz = i z

z^{2} = 1 - i

What is the answer to (a+b+3)+(8+b)i=2a+(3a-b)i ?
The answer to (a+b+3)+(8+b)i=2a+(3a-b)i is a=2,b=-1