What is the answer to ((18+i))/(4+3i)=a+bi ?

The answer to ((18+i))/(4+3i)=a+bi is a=3,b=-2

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((18+i))/(4+3i)=a+bi

\frac{( 18 + i )}{4 + 3 i} = a + bi

a = 3, b = - 2

Solution steps

\frac{( 18 + i )}{4 + 3 i} = a + bi

Simplify

\frac{18 + i}{4 + 3 i} : 3 - 2 i

3 - 2 i = a + bi

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 = a - 2 = b]

[3 = a - 2 = b] : a = 3, b = - 2

a = 3, b = - 2

in (in (in x)) = y

(1 + x) = (1 + r) \cdot (1 + i)

x^{2} - 8 x i - 25 = 0

(x + i y) + 2 (x - i y) = \frac{2 i}{1 + 3 i}

3 i y^{2} - y + 2 i = 0

What is the answer to ((18+i))/(4+3i)=a+bi ?
The answer to ((18+i))/(4+3i)=a+bi is a=3,b=-2