What is the answer to x+3y+(3x-y)i=6+6i ?

The answer to x+3y+(3x-y)i=6+6i is x= 12/5 ,y= 6/5

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x+3y+(3x-y)i=6+6i

x + 3 y + (3 x - y) i = 6 + 6 i

x = \frac{12}{5}, y = \frac{6}{5}

Solution steps

x + 3 y + (3 x - y) i = 6 + 6 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + 3 y = 6 3 x - y = 6]

[x + 3 y = 6 3 x - y = 6] : x = \frac{12}{5}, y = \frac{6}{5}

x = \frac{12}{5}, y = \frac{6}{5}

z^{2} - 2 z i - 2 = 0

(x + i y) - 2 (x - i y) + 7 - 6 i = 0

(2 x - i) + (x - 2 y i) = - 2 i

\frac{( 1 - z )}{( 1 + z )} = 2 i

(x + i y)^{2} + i x + y - 4 = 0

What is the answer to x+3y+(3x-y)i=6+6i ?
The answer to x+3y+(3x-y)i=6+6i is x= 12/5 ,y= 6/5