What are the solutions to the equation (x-2)^2-5=-1 ?

The solutions to the equation (x-2)^2-5=-1 are x=4,x=0

Find the zeros of (x-2)^2-5=-1

The zeros of (x-2)^2-5=-1 are x=4,x=0

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(x - 2)^{2} - 5 = - 1

x = 4, x = 0

Solution steps

(x - 2)^{2} - 5 = - 1

Move

5

to the right side

(x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 4 : x = 4

Solve

x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

u^{2} + 6 u + 9 = 0

10 x^{3} - 35 x^{2} - 20 x

6 x^{2} - 180 x + 1296 = 0

7^{\frac{3}{2}}

- \frac{1}{7} x = 3

What are the solutions to the equation (x-2)^2-5=-1 ?
The solutions to the equation (x-2)^2-5=-1 are x=4,x=0
Find the zeros of (x-2)^2-5=-1
The zeros of (x-2)^2-5=-1 are x=4,x=0