What are the solutions to the equation 6x^2-180x+1296=0 ?

The solutions to the equation 6x^2-180x+1296=0 are x=18,x=12

Find the zeros of 6x^2-180x+1296=0

The zeros of 6x^2-180x+1296=0 are x=18,x=12

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6 x^{2} - 180 x + 1296 = 0

x = 18, x = 12

Solution steps

6 x^{2} - 180 x + 1296 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 180 ) \pm ( - 180 ) ^{2} - 4 \cdot 6 \cdot 1296}{2 \cdot 6}

(- 180)^{2} - 4 \cdot 6 \cdot 1296 = 36

x_{1, 2} = \frac{- ( - 180 ) \pm 36}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 180 ) + 36}{2 \cdot 6}, x_{2} = \frac{- ( - 180 ) - 36}{2 \cdot 6}

x = \frac{- ( - 180 ) + 36}{2 \cdot 6} : 18

x = \frac{- ( - 180 ) - 36}{2 \cdot 6} : 12

The solutions to the quadratic equation are:

x = 18, x = 12

7^{\frac{3}{2}}

- \frac{1}{7} x = 3

(7 x + 22)^{2} = 80

\frac{6}{8}

(125 x^{- 3} y^{- 15})^{\frac{5}{3}}

What are the solutions to the equation 6x^2-180x+1296=0 ?
The solutions to the equation 6x^2-180x+1296=0 are x=18,x=12
Find the zeros of 6x^2-180x+1296=0
The zeros of 6x^2-180x+1296=0 are x=18,x=12