What is the answer to 4x+4iy-23=5ix+5i^2y+2i ?

The answer to 4x+4iy-23=5ix+5i^2y+2i is x=2,y=3

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4x+4iy-23=5ix+5i^2y+2i

4 x + 4 i y - 23 = 5 i x + 5 i^{2} y + 2 i

x = 2, y = 3

Solution steps

4 x + 4 i y - 23 = 5 i x + 5 i^{2} y + 2 i

Simplify

(4 x - 23) + 4 i y = - 5 y + i (2 + 5 x)

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[4 x - 23 = - 5 y 4 y = 2 + 5 x]

[4 x - 23 = - 5 y 4 y = 2 + 5 x] : x = 2, y = 3

x = 2, y = 3

z^{2} - (3 + 2 i) z + (1 + 3 i) = 0

(x - (3 - 4 i)) (x - (3 + 4 i)) = 0

(x + i) (3 - i y) = 1 + 13 i

(a - bi) + (b + ai) = 5 + i

z^{2} - 2 z = 3 i

What is the answer to 4x+4iy-23=5ix+5i^2y+2i ?
The answer to 4x+4iy-23=5ix+5i^2y+2i is x=2,y=3